Percentage practice questions for competitive exams

The price of an article is decreased by 20%. By what percent he price of that article should be increased to restore in its previous price.
a. 20%
b. 15%
c. 25%
d. 30%

Answer: c. 24%
Solutin: Let the price of the article be 100
Price of the article after 20% reduction = 80
Percentage need to be increased to restore its previous value is :
$80 \times \frac{x}{100} = 20$
$x = 20 \times \frac{100}{80} = 25$

The price of an article is first decreased by 20% and then increased by 30%. If the resulting price of the article is 416rs then the orignal price of the article is ?
a. 400 rs.
b. 405 rs.
c. 410 rs.
d. 390 rs.

Answer: a. 400 rs.
Solution: Let the original price of the article be x
According to the question:
$x \times \frac{80}{100} \times \frac{130}{100} = 416$
$x = \frac{416 \times 100 \times 100}{80 \times 130} = 400$

If he population of a town is 60,000 and its annual increase is 10%. Then its correct population at the end of 3 years will be?
a. 66,000
b. 76,780
c. 79,860
d. 80,000

Answer: c. 79860
Solution: $60,000 \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100}$
$= 79860$

A’s salary is increased by 5 percent. If his present salary is 1680rs. then what was his previous salary?
a. 1500rs.
b. 1550rs.
c. 1600rs.
d. 1650rs.

Answer: c. 1600rs.
Solution: Let A’s previous salary be x
$x \times \frac{105}{100} = 1680$
$x = 1680 \times \frac{100}{105} = 1600$

In a town, the population was 8000. In one year, male population increased by 10% and female population increased by 8% but the total population of the town was increased by 9%. The number of males in the town was?
a. 4000
b. 5000
c. 6000
d. 6500

Answer: a. 4000
Solutin: Let the numbers of the males in the town be x
No. of females in the town is (8000-x)
According to the question: $x \times \frac{110}{100} + (8000 - x) \times \frac{108}{100} = 8720$
$110 x + 8000 \times 108 - 108 x = 872000$
$2 x + 864000 = 872000$
$2 x = 8000$
$x = 4000$

Answer:

The value of a machine depreciates every year at the rate of 10% on its value at the beginning of that year. If the current value of machine is 3645rs. then its worth 3 years ago was?
a. 4000
b. 4250
c. 4500
d. 5000

Answer: d. 5000
Solution: Let the value of the machine 3 years ago be x
$3645 = x \times \frac{90}{100} \times \frac{90}{100} \times \frac{90}{100}$
$x = 3645 \times \frac{10}{9} \times \frac{10}{9} \times \frac{10}{9} = 5000$

The population of a town is 20,000. Out of them one fifth are females and rest of them are males. 20% of the males and 20% of the females are uneducated. What percentage of the population is educated?
a. 60%
b. 65%
c. 70%
d. 80%

Answer: d. 80
Solution: No. of females in town is one fifth of 20,000 which is 4000
No. of males in the town is 20,000-4,000 = 16000
uneducated males in the town are $16000 \times \frac{20}{100} = 3200$
Uneducated females in the town are $4,000 \times \frac{20}{100} = 800$
Total educated people in the town are : 20000-(3200=800)= 16000
Percentage of educated people in the town are
$20000 \times \frac{x}{100} = 16000$
$x = \frac{16000}{200} = 80$

What percent of 2.4kg is 48gm?
a. 1%
b. 10%
c. 2%
d. 20%

Answer: c. 2%
Solution: By converting 48gm to Kg we get 0.048kg
$2.4 \times \frac{x}{100} = \frac{48}{1000}$
$x = 2$

If 125% of x is 100. Then x is?
a. 80
b. 100
c. 120
d. 75

Answer: a. 80
Solution: According to the question:
$x \times \frac{125}{100} = 100$
$x = 100 \times \frac{100}{125} = 80$

If three-fifth of sixty percent of a number is 36, then the number is?
a. 50
b. 75
c. 100
d. 150

Answer: c. 100
Solution: According to the question :
$\frac{3}{5} \times \frac{60}{100} \times x = 36$
$x = 100$

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Pariksha buddy

Percentage practice questions for competitive exams

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