Percentage practice questions for competitive exams

Answer: a. 1500
Solution: Let the salary of Ramesh be x
If he saves 25% of his salary then his expenditure is 75% of his salary
$x\times \frac{75}{100}=6000 \Rightarrow x=6000\times \frac{4}{3}=8000$

Answer: b. 25%
Solution: Let the salary of A’s be 100
The salary of A’s after reduction will be :
$100\times \frac{50}{100}\times \frac{150}{100}=75$
A’s salary after reduction is 75 that means A’s losed 25% of his salary.

Answer: c. 23:17
Solution: Let that two numbers be x and y
According to the question:
$(x–y)=\frac{15}{100}(x+y) \Rightarrow (x–y)=\frac{3}{20}(x+y)$
$\Rightarrow 20x–20y=3x+3y\Rightarrow 20x–3x=20y+3y$
$\Rightarrow 17x=23y \Rightarrow \frac{x}{y}=\frac{23}{17}=23:17$

Answer: c. 50%
Solution: Total minutes in a day = 24×60= 1440
Percentage will be :
$1440\times \frac{x}{100}=72\Rightarrow x=72\times \frac{100}{1440}=5$

Answer: a. 21,600
Solution: Population of the town after two years will be:
$\mathrm{20,000}\times \frac{90}{100}\times \frac{120}{100}=21600$

Answer: c. 500
Solution: According to the question:
933-25)% of x = 40
8% of x = 40
$x=\frac{40\times 100}{8}=500$

Answer: b. 5%
Solution: 50cm in meter will be 0.5m
Let see how much percent of 10m is 0.5m
$10\times \frac{x}{100}=0.5\Rightarrow x= 5$

Answer: c. 8% increase
Solution: Let that number be 100
After change the number will become
$100\times \frac{120}{100}\times \frac{90}{100}=108$
108 is 8% more than 100

Answer: b. 1,45,200
Solution: The population of the town after two years will be
$1,\mathrm{20,000}\times \frac{110}{100}\times \frac{110}{100}=1,\mathrm{45,200}$